(X+5)=(3x-4)+(6x-19)

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Solution for (X+5)=(3x-4)+(6x-19) equation: 



(X+5)=(3X-4)+(6X-19)

We move all terms to the left:

(X+5)-((3X-4)+(6X-19))=0

We get rid of parentheses

X-((3X-4)+(6X-19))+5=0



We calculate terms in parentheses: -((3X-4)+(6X-19)), so:

(3X-4)+(6X-19)

We get rid of parentheses

3X+6X-4-19

We add all the numbers together, and all the variables

9X-23

Back to the equation:

-(9X-23)



We get rid of parentheses

X-9X+23+5=0

We add all the numbers together, and all the variables

-8X+28=0

We move all terms containing X to the left, all other terms to the right

-8X=-28

X=-28/-8

X=3+1/2

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