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(X+5)X=3300
We move all terms to the left:
(X+5)X-(3300)=0
We multiply parentheses
X^2+5X-3300=0
a = 1; b = 5; c = -3300;
Δ = b2-4ac
Δ = 52-4·1·(-3300)
Δ = 13225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13225}=115$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-115}{2*1}=\frac{-120}{2} =-60 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+115}{2*1}=\frac{110}{2} =55 $
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