(X+50)+(110-2x)+(5x-40)=180

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Solution for (X+50)+(110-2x)+(5x-40)=180 equation: 



(X+50)+(110-2X)+(5X-40)=180

We move all terms to the left:

(X+50)+(110-2X)+(5X-40)-(180)=0

We add all the numbers together, and all the variables

(X+50)+(-2X+110)+(5X-40)-180=0

We get rid of parentheses

X-2X+5X+50+110-40-180=0

We add all the numbers together, and all the variables

4X-60=0

We move all terms containing X to the left, all other terms to the right

4X=60

X=60/4

X=15

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