(X+50)+(3x-20)+(2x+30)=360

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Solution for (X+50)+(3x-20)+(2x+30)=360 equation: 



(X+50)+(3X-20)+(2X+30)=360

We move all terms to the left:

(X+50)+(3X-20)+(2X+30)-(360)=0

We get rid of parentheses

X+3X+2X+50-20+30-360=0

We add all the numbers together, and all the variables

6X-300=0

We move all terms containing X to the left, all other terms to the right

6X=300

X=300/6

X=50

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