(X+50)+(3x-20)+(2x+30)=360

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Solution for (X+50)+(3x-20)+(2x+30)=360 equation:



(X+50)+(3X-20)+(2X+30)=360
We move all terms to the left:
(X+50)+(3X-20)+(2X+30)-(360)=0
We get rid of parentheses
X+3X+2X+50-20+30-360=0
We add all the numbers together, and all the variables
6X-300=0
We move all terms containing X to the left, all other terms to the right
6X=300
X=300/6
X=50

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