(X+6)+(x+6)+(x+2)+(x+2)=(x+4)+(x+4)+(2x-2)+(2x-2)

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Solution for (X+6)+(x+6)+(x+2)+(x+2)=(x+4)+(x+4)+(2x-2)+(2x-2) equation: 



(X+6)+(X+6)+(X+2)+(X+2)=(X+4)+(X+4)+(2X-2)+(2X-2)

We move all terms to the left:

(X+6)+(X+6)+(X+2)+(X+2)-((X+4)+(X+4)+(2X-2)+(2X-2))=0

We get rid of parentheses

X+X+X+X-((X+4)+(X+4)+(2X-2)+(2X-2))+6+6+2+2=0



We calculate terms in parentheses: -((X+4)+(X+4)+(2X-2)+(2X-2)), so:

(X+4)+(X+4)+(2X-2)+(2X-2)

We get rid of parentheses

X+X+2X+2X+4+4-2-2

We add all the numbers together, and all the variables

6X+4

Back to the equation:

-(6X+4)



We add all the numbers together, and all the variables

4X-(6X+4)+16=0

We get rid of parentheses

4X-6X-4+16=0

We add all the numbers together, and all the variables

-2X+12=0

We move all terms containing X to the left, all other terms to the right

-2X=-12

X=-12/-2

X=+6

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