(X+6)-10+2x=3x+4(x-5)-3x+2

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Solution for (X+6)-10+2x=3x+4(x-5)-3x+2 equation:



(X+6)-10+2X=3X+4(X-5)-3X+2
We move all terms to the left:
(X+6)-10+2X-(3X+4(X-5)-3X+2)=0
We add all the numbers together, and all the variables
2X+(X+6)-(3X+4(X-5)-3X+2)-10=0
We get rid of parentheses
2X+X-(3X+4(X-5)-3X+2)+6-10=0
We calculate terms in parentheses: -(3X+4(X-5)-3X+2), so:
3X+4(X-5)-3X+2
We add all the numbers together, and all the variables
4(X-5)+2
We multiply parentheses
4X-20+2
We add all the numbers together, and all the variables
4X-18
Back to the equation:
-(4X-18)
We add all the numbers together, and all the variables
3X-(4X-18)-4=0
We get rid of parentheses
3X-4X+18-4=0
We add all the numbers together, and all the variables
-1X+14=0
We move all terms containing X to the left, all other terms to the right
-X=-14
X=-14/-1
X=+14

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