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(X+7)(2X+5)=0
We multiply parentheses ..
(+2X^2+5X+14X+35)=0
We get rid of parentheses
2X^2+5X+14X+35=0
We add all the numbers together, and all the variables
2X^2+19X+35=0
a = 2; b = 19; c = +35;
Δ = b2-4ac
Δ = 192-4·2·35
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-9}{2*2}=\frac{-28}{4} =-7 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+9}{2*2}=\frac{-10}{4} =-2+1/2 $
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