(X+7)(x-3)=X2+3x-16

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Solution for (X+7)(x-3)=X2+3x-16 equation:



(X+7)(X-3)=X2+3X-16
We move all terms to the left:
(X+7)(X-3)-(X2+3X-16)=0
We add all the numbers together, and all the variables
-(+X^2+3X-16)+(X+7)(X-3)=0
We get rid of parentheses
-X^2-3X+(X+7)(X-3)+16=0
We multiply parentheses ..
-X^2+(+X^2-3X+7X-21)-3X+16=0
We add all the numbers together, and all the variables
-1X^2+(+X^2-3X+7X-21)-3X+16=0
We get rid of parentheses
-1X^2+X^2-3X+7X-3X-21+16=0
We add all the numbers together, and all the variables
X-5=0
We move all terms containing X to the left, all other terms to the right
X=5

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