(X+9)(x+4)=(x-5)(x-3)

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Solution for (X+9)(x+4)=(x-5)(x-3) equation: 



(X+9)(X+4)=(X-5)(X-3)

We move all terms to the left:

(X+9)(X+4)-((X-5)(X-3))=0

We multiply parentheses ..

(+X^2+4X+9X+36)-((X-5)(X-3))=0



We calculate terms in parentheses: -((X-5)(X-3)), so:

(X-5)(X-3)

We multiply parentheses ..

(+X^2-3X-5X+15)

We get rid of parentheses

X^2-3X-5X+15

We add all the numbers together, and all the variables

X^2-8X+15

Back to the equation:

-(X^2-8X+15)



We get rid of parentheses

X^2-X^2+4X+9X+8X+36-15=0

We add all the numbers together, and all the variables

21X+21=0

We move all terms containing X to the left, all other terms to the right

21X=-21

X=-21/21

X=-1

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