(X-1)(x-2)=(x+3)(x+4)

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Solution for (X-1)(x-2)=(x+3)(x+4) equation: 



(X-1)(X-2)=(X+3)(X+4)

We move all terms to the left:

(X-1)(X-2)-((X+3)(X+4))=0

We multiply parentheses ..

(+X^2-2X-1X+2)-((X+3)(X+4))=0



We calculate terms in parentheses: -((X+3)(X+4)), so:

(X+3)(X+4)

We multiply parentheses ..

(+X^2+4X+3X+12)

We get rid of parentheses

X^2+4X+3X+12

We add all the numbers together, and all the variables

X^2+7X+12

Back to the equation:

-(X^2+7X+12)



We get rid of parentheses

X^2-X^2-2X-1X-7X+2-12=0

We add all the numbers together, and all the variables

-10X-10=0

We move all terms containing X to the left, all other terms to the right

-10X=10

X=10/-10

X=-1

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