(X-1)(x-5)=x2+4x-2

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Solution for (X-1)(x-5)=x2+4x-2 equation: 



(X-1)(X-5)=X2+4X-2

We move all terms to the left:

(X-1)(X-5)-(X2+4X-2)=0

We add all the numbers together, and all the variables

-(+X^2+4X-2)+(X-1)(X-5)=0

We get rid of parentheses

-X^2-4X+(X-1)(X-5)+2=0

We multiply parentheses ..

-X^2+(+X^2-5X-1X+5)-4X+2=0

We add all the numbers together, and all the variables

-1X^2+(+X^2-5X-1X+5)-4X+2=0

We get rid of parentheses

-1X^2+X^2-5X-1X-4X+5+2=0

We add all the numbers together, and all the variables

-10X+7=0

We move all terms containing X to the left, all other terms to the right

-10X=-7

X=-7/-10

X=7/10

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