(X-1)2+(x+1)2=2x2+8x+2

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Solution for (X-1)2+(x+1)2=2x2+8x+2 equation: 



(X-1)2+(X+1)2=2X^2+8X+2

We move all terms to the left:

(X-1)2+(X+1)2-(2X^2+8X+2)=0

We multiply parentheses

2X+2X-(2X^2+8X+2)-2+2=0

We get rid of parentheses

-2X^2+2X+2X-8X-2-2+2=0

We add all the numbers together, and all the variables

-2X^2-4X-2=0

a = -2; b = -4; c = -2;
Δ = b2-4ac
Δ = -42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{4}{-4}=-1$

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