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(X-10)(X-6)=32
We move all terms to the left:
(X-10)(X-6)-(32)=0
We multiply parentheses ..
(+X^2-6X-10X+60)-32=0
We get rid of parentheses
X^2-6X-10X+60-32=0
We add all the numbers together, and all the variables
X^2-16X+28=0
a = 1; b = -16; c = +28;
Δ = b2-4ac
Δ = -162-4·1·28
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-12}{2*1}=\frac{4}{2} =2 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+12}{2*1}=\frac{28}{2} =14 $
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