(X-12)+(x+12)+(4x-80)=180

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Solution for (X-12)+(x+12)+(4x-80)=180 equation: 



(X-12)+(X+12)+(4X-80)=180

We move all terms to the left:

(X-12)+(X+12)+(4X-80)-(180)=0

We get rid of parentheses

X+X+4X-12+12-80-180=0

We add all the numbers together, and all the variables

6X-260=0

We move all terms containing X to the left, all other terms to the right

6X=260

X=260/6

X=43+1/3

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