(X-12)3x-12=3

Solution for (X-12)3x-12=3 equation:

(X-12)3X-12=3

We move all terms to the left:

(X-12)3X-12-(3)=0

We add all the numbers together, and all the variables

(X-12)3X-15=0

We multiply parentheses

3X^2-36X-15=0

a = 3; b = -36; c = -15;
Δ = b2-4ac
Δ = -362-4·3·(-15)
Δ = 1476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1476}=\sqrt{36*41}=\sqrt{36}*\sqrt{41}=6\sqrt{41}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-6\sqrt{41}}{2*3}=\frac{36-6\sqrt{41}}{6}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+6\sqrt{41}}{2*3}=\frac{36+6\sqrt{41}}{6}
$