(X-16)+(2x+40)+(x)=180

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Solution for (X-16)+(2x+40)+(x)=180 equation: 



(X-16)+(2X+40)+(X)=180

We move all terms to the left:

(X-16)+(2X+40)+(X)-(180)=0

We add all the numbers together, and all the variables

X+(X-16)+(2X+40)-180=0

We get rid of parentheses

X+X+2X-16+40-180=0

We add all the numbers together, and all the variables

4X-156=0

We move all terms containing X to the left, all other terms to the right

4X=156

X=156/4

X=39

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