(X-2)(2x+5)-2(3x)=2(x-2)x

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Solution for (X-2)(2x+5)-2(3x)=2(x-2)x equation: 



(X-2)(2X+5)-2(3X)=2(X-2)X

We move all terms to the left:

(X-2)(2X+5)-2(3X)-(2(X-2)X)=0

We add all the numbers together, and all the variables

-23X+(X-2)(2X+5)-(2(X-2)X)=0

We multiply parentheses ..

(+2X^2+5X-4X-10)-23X-(2(X-2)X)=0



We calculate terms in parentheses: -(2(X-2)X), so:

2(X-2)X

We multiply parentheses

2X^2-4X

Back to the equation:

-(2X^2-4X)



We get rid of parentheses

2X^2-2X^2+5X-4X-23X+4X-10=0

We add all the numbers together, and all the variables

-18X-10=0

We move all terms containing X to the left, all other terms to the right

-18X=10

X=10/-18

X=-5/9

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