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(X-2)(3X-2)=8
We move all terms to the left:
(X-2)(3X-2)-(8)=0
We multiply parentheses ..
(+3X^2-2X-6X+4)-8=0
We get rid of parentheses
3X^2-2X-6X+4-8=0
We add all the numbers together, and all the variables
3X^2-8X-4=0
a = 3; b = -8; c = -4;
Δ = b2-4ac
Δ = -82-4·3·(-4)
Δ = 112
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{112}=\sqrt{16*7}=\sqrt{16}*\sqrt{7}=4\sqrt{7}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-4\sqrt{7}}{2*3}=\frac{8-4\sqrt{7}}{6} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+4\sqrt{7}}{2*3}=\frac{8+4\sqrt{7}}{6} $
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