(X-2)(X-4)=(x-2)(x+1)

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Solution for (X-2)(X-4)=(x-2)(x+1) equation: 



(X-2)(X-4)=(X-2)(X+1)

We move all terms to the left:

(X-2)(X-4)-((X-2)(X+1))=0

We multiply parentheses ..

(+X^2-4X-2X+8)-((X-2)(X+1))=0



We calculate terms in parentheses: -((X-2)(X+1)), so:

(X-2)(X+1)

We multiply parentheses ..

(+X^2+X-2X-2)

We get rid of parentheses

X^2+X-2X-2

We add all the numbers together, and all the variables

X^2-1X-2

Back to the equation:

-(X^2-1X-2)



We get rid of parentheses

X^2-X^2-4X-2X+1X+8+2=0

We add all the numbers together, and all the variables

-5X+10=0

We move all terms containing X to the left, all other terms to the right

-5X=-10

X=-10/-5

X=+2

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