(X-2)(x+10)=-11

Solution for (X-2)(x+10)=-11 equation:

(X-2)(X+10)=-11

We move all terms to the left:

(X-2)(X+10)-(-11)=0

We add all the numbers together, and all the variables

(X-2)(X+10)+11=0

We multiply parentheses ..

(+X^2+10X-2X-20)+11=0

We get rid of parentheses

X^2+10X-2X-20+11=0

We add all the numbers together, and all the variables

X^2+8X-9=0

a = 1; b = 8; c = -9;
Δ = b2-4ac
Δ = 82-4·1·(-9)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-10}{2*1}=\frac{-18}{2}
=-9
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+10}{2*1}=\frac{2}{2}
=1
$