(X-2)(x+6=-7

Solution for (X-2)(x+6=-7 equation:

(X-2)(X+6=-7

We move all terms to the left:

(X-2)(X+6-(-7)=0


We calculate terms in parentheses: +(X-2)(X+6-(-7), so:

X-2)(X+6-(-7

We add all the numbers together, and all the variables

X-2)(X

Back to the equation:

+(X-2)(X)


We multiply parentheses

X^2-2X=0

a = 1; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·1·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*1}=\frac{0}{2}
=0
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*1}=\frac{4}{2}
=2
$