(X-2)(x-5)=(x+5)(x+9)

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Solution for (X-2)(x-5)=(x+5)(x+9) equation: 



(X-2)(X-5)=(X+5)(X+9)

We move all terms to the left:

(X-2)(X-5)-((X+5)(X+9))=0

We multiply parentheses ..

(+X^2-5X-2X+10)-((X+5)(X+9))=0



We calculate terms in parentheses: -((X+5)(X+9)), so:

(X+5)(X+9)

We multiply parentheses ..

(+X^2+9X+5X+45)

We get rid of parentheses

X^2+9X+5X+45

We add all the numbers together, and all the variables

X^2+14X+45

Back to the equation:

-(X^2+14X+45)



We get rid of parentheses

X^2-X^2-5X-2X-14X+10-45=0

We add all the numbers together, and all the variables

-21X-35=0

We move all terms containing X to the left, all other terms to the right

-21X=35

X=35/-21

X=-1+2/3

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