(X-2)+(x+4)=(x-3)+(x+4)+(x+5)

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Solution for (X-2)+(x+4)=(x-3)+(x+4)+(x+5) equation: 



(X-2)+(X+4)=(X-3)+(X+4)+(X+5)

We move all terms to the left:

(X-2)+(X+4)-((X-3)+(X+4)+(X+5))=0

We get rid of parentheses

X+X-((X-3)+(X+4)+(X+5))-2+4=0



We calculate terms in parentheses: -((X-3)+(X+4)+(X+5)), so:

(X-3)+(X+4)+(X+5)

We get rid of parentheses

X+X+X-3+4+5

We add all the numbers together, and all the variables

3X+6

Back to the equation:

-(3X+6)



We add all the numbers together, and all the variables

2X-(3X+6)+2=0

We get rid of parentheses

2X-3X-6+2=0

We add all the numbers together, and all the variables

-1X-4=0

We move all terms containing X to the left, all other terms to the right

-X=4

X=4/-1

X=-4

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