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(X-2)+X+(X+2)=30+(X+2)
We move all terms to the left:
(X-2)+X+(X+2)-(30+(X+2))=0
We add all the numbers together, and all the variables
X+(X-2)+(X+2)-(30+(X+2))=0
We get rid of parentheses
X+X+X-(30+(X+2))-2+2=0
We calculate terms in parentheses: -(30+(X+2)), so:We add all the numbers together, and all the variables
30+(X+2)
determiningTheFunctionDomain (X+2)+30
We get rid of parentheses
X+2+30
We add all the numbers together, and all the variables
X+32
Back to the equation:
-(X+32)
3X-(X+32)=0
We get rid of parentheses
3X-X-32=0
We add all the numbers together, and all the variables
2X-32=0
We move all terms containing X to the left, all other terms to the right
2X=32
X=32/2
X=16
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