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(X-2012)(3X+8)=0
We multiply parentheses ..
(+3X^2+8X-6036X-16096)=0
We get rid of parentheses
3X^2+8X-6036X-16096=0
We add all the numbers together, and all the variables
3X^2-6028X-16096=0
a = 3; b = -6028; c = -16096;
Δ = b2-4ac
Δ = -60282-4·3·(-16096)
Δ = 36529936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36529936}=6044$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6028)-6044}{2*3}=\frac{-16}{6} =-2+2/3 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6028)+6044}{2*3}=\frac{12072}{6} =2012 $
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