(X-2012)(3x+8)=0

Solution for (X-2012)(3x+8)=0 equation:

(X-2012)(3X+8)=0

We multiply parentheses ..

(+3X^2+8X-6036X-16096)=0

We get rid of parentheses

3X^2+8X-6036X-16096=0

We add all the numbers together, and all the variables

3X^2-6028X-16096=0

a = 3; b = -6028; c = -16096;
Δ = b2-4ac
Δ = -60282-4·3·(-16096)
Δ = 36529936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36529936}=6044$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6028)-6044}{2*3}=\frac{-16}{6}
=-2+2/3
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6028)+6044}{2*3}=\frac{12072}{6}
=2012
$