(X-3)(2x+11)=0

Solution for (X-3)(2x+11)=0 equation:

(X-3)(2X+11)=0

We multiply parentheses ..

(+2X^2+11X-6X-33)=0

We get rid of parentheses

2X^2+11X-6X-33=0

We add all the numbers together, and all the variables

2X^2+5X-33=0

a = 2; b = 5; c = -33;
Δ = b2-4ac
Δ = 52-4·2·(-33)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-17}{2*2}=\frac{-22}{4}
=-5+1/2
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+17}{2*2}=\frac{12}{4}
=3
$