(X-3)(x+4)=(x-11)(x+6)

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Solution for (X-3)(x+4)=(x-11)(x+6) equation: 



(X-3)(X+4)=(X-11)(X+6)

We move all terms to the left:

(X-3)(X+4)-((X-11)(X+6))=0

We multiply parentheses ..

(+X^2+4X-3X-12)-((X-11)(X+6))=0



We calculate terms in parentheses: -((X-11)(X+6)), so:

(X-11)(X+6)

We multiply parentheses ..

(+X^2+6X-11X-66)

We get rid of parentheses

X^2+6X-11X-66

We add all the numbers together, and all the variables

X^2-5X-66

Back to the equation:

-(X^2-5X-66)



We get rid of parentheses

X^2-X^2+4X-3X+5X-12+66=0

We add all the numbers together, and all the variables

6X+54=0

We move all terms containing X to the left, all other terms to the right

6X=-54

X=-54/6

X=-9

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