(X-3)(x+4)=(x-2)(x+5)

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Solution for (X-3)(x+4)=(x-2)(x+5) equation: 



(X-3)(X+4)=(X-2)(X+5)

We move all terms to the left:

(X-3)(X+4)-((X-2)(X+5))=0

We multiply parentheses ..

(+X^2+4X-3X-12)-((X-2)(X+5))=0



We calculate terms in parentheses: -((X-2)(X+5)), so:

(X-2)(X+5)

We multiply parentheses ..

(+X^2+5X-2X-10)

We get rid of parentheses

X^2+5X-2X-10

We add all the numbers together, and all the variables

X^2+3X-10

Back to the equation:

-(X^2+3X-10)



We get rid of parentheses

X^2-X^2+4X-3X-3X-12+10=0

We add all the numbers together, and all the variables

-2X-2=0

We move all terms containing X to the left, all other terms to the right

-2X=2

X=2/-2

X=-1

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