(X-3)(x+4)=(x-2)(x-2)

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Solution for (X-3)(x+4)=(x-2)(x-2) equation: 



(X-3)(X+4)=(X-2)(X-2)

We move all terms to the left:

(X-3)(X+4)-((X-2)(X-2))=0

We multiply parentheses ..

(+X^2+4X-3X-12)-((X-2)(X-2))=0



We calculate terms in parentheses: -((X-2)(X-2)), so:

(X-2)(X-2)

We multiply parentheses ..

(+X^2-2X-2X+4)

We get rid of parentheses

X^2-2X-2X+4

We add all the numbers together, and all the variables

X^2-4X+4

Back to the equation:

-(X^2-4X+4)



We get rid of parentheses

X^2-X^2+4X-3X+4X-12-4=0

We add all the numbers together, and all the variables

5X-16=0

We move all terms containing X to the left, all other terms to the right

5X=16

X=16/5

X=3+1/5

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