(X-3)(x+5)=x27x-15

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Solution for (X-3)(x+5)=x27x-15 equation: 



(X-3)(X+5)=X27X-15

We move all terms to the left:

(X-3)(X+5)-(X27X-15)=0

We get rid of parentheses

(X-3)(X+5)-X27X+15=0

We multiply parentheses ..

(+X^2+5X-3X-15)-X27X+15=0

We get rid of parentheses

X^2+5X-3X-X27X-15+15=0

We add all the numbers together, and all the variables

X^2+2X-X27X=0

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