(X-3)(x+6)=(x+5)(x-5)

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Solution for (X-3)(x+6)=(x+5)(x-5) equation: 



(X-3)(X+6)=(X+5)(X-5)

We move all terms to the left:

(X-3)(X+6)-((X+5)(X-5))=0

We use the square of the difference formula

X^2+(X-3)(X+6)+25=0

We multiply parentheses ..

X^2+(+X^2+6X-3X-18)+25=0

We get rid of parentheses

X^2+X^2+6X-3X-18+25=0

We add all the numbers together, and all the variables

2X^2+3X+7=0

a = 2; b = 3; c = +7;
Δ = b2-4ac
Δ = 32-4·2·7
Δ = -47
Delta is less than zero, so there is no solution for the equation

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