(X-3)(x-5)-(x-4)(x-6)=3

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Solution for (X-3)(x-5)-(x-4)(x-6)=3 equation: 



(X-3)(X-5)-(X-4)(X-6)=3

We move all terms to the left:

(X-3)(X-5)-(X-4)(X-6)-(3)=0

We multiply parentheses ..

(+X^2-5X-3X+15)-(X-4)(X-6)-3=0

We get rid of parentheses

X^2-5X-3X-(X-4)(X-6)+15-3=0

We multiply parentheses ..

X^2-(+X^2-6X-4X+24)-5X-3X+15-3=0

We add all the numbers together, and all the variables

X^2-(+X^2-6X-4X+24)-8X+12=0

We get rid of parentheses

X^2-X^2+6X+4X-8X-24+12=0

We add all the numbers together, and all the variables

2X-12=0

We move all terms containing X to the left, all other terms to the right

2X=12

X=12/2

X=6

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