(X-3)+x+(x+4)=196

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Solution for (X-3)+x+(x+4)=196 equation: 



(X-3)+X+(X+4)=196

We move all terms to the left:

(X-3)+X+(X+4)-(196)=0

We add all the numbers together, and all the variables

X+(X-3)+(X+4)-196=0

We get rid of parentheses

X+X+X-3+4-196=0

We add all the numbers together, and all the variables

3X-195=0

We move all terms containing X to the left, all other terms to the right

3X=195

X=195/3

X=65

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