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(X-3)/(2X)=(X-5)/X
We move all terms to the left:
(X-3)/(2X)-((X-5)/X)=0
Domain of the equation: 2X!=0
X!=0/2
X!=0
X∈R
Domain of the equation: X)!=0We calculate fractions
X!=0/1
X!=0
X∈R
(X-3)*X)/2X^2+(-((X-5)*2X)/2X^2=0
We calculate fractions
((X-3)*X)*2X^2)/(2X^2+(*2X^2)+(-((X-5)*2X)*2X^2)/(2X^2+(*2X^2)=0
We calculate terms in parentheses: +(-((X-5)*2X)*2X^2)/(2X^2+(*2X^2), so:We get rid of parentheses
-((X-5)*2X)*2X^2)/(2X^2+(*2X^2
We multiply all the terms by the denominator
-((X-5)*2X)*2X^2)+((*2X^2)*(2X^2
Back to the equation:
+(-((X-5)*2X)*2X^2)+((*2X^2)*(2X^2)
((X-3)*X)*2X^2)/(2X^2+*2X^2+(-((X-5)*2X)*2X^2)+((*2X^2)*2X^2=0
We multiply all the terms by the denominator
((X-3)*X)*2X^2)+(*2X^2)*(2X^2+((-((X-5)*2X)*2X^2))*(2X^2+(((*2X^2)*2X^2)*(2X^2=0
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