(X-3)/6=(3x+2)/4

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Solution for (X-3)/6=(3x+2)/4 equation:



(X-3)/6=(3X+2)/4
We move all terms to the left:
(X-3)/6-((3X+2)/4)=0
We calculate fractions
X/()+(-((3X+2)*6)/()=0
We calculate terms in parentheses: +(-((3X+2)*6)/(), so:
-((3X+2)*6)/(
We multiply all the terms by the denominator
-((3X+2)*6)
We calculate terms in parentheses: -((3X+2)*6), so:
(3X+2)*6
We multiply parentheses
18X+12
Back to the equation:
-(18X+12)
We get rid of parentheses
-18X-12
Back to the equation:
+(-18X-12)
We get rid of parentheses
X/()-18X-12=0
We multiply all the terms by the denominator
X-18X*()-12*()=0
We add all the numbers together, and all the variables
X-18X*()=0

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