(X-3)=-(7/2)(y-7)

Solution for (X-3)=-(7/2)(y-7) equation:

(X-3)=-(7/2)(X-7)

We move all terms to the left:

(X-3)-(-(7/2)(X-7))=0


Domain of the equation: 2)(X-7))!=0

X∈R


We add all the numbers together, and all the variables

(X-3)-(-(+7/2)(X-7))=0

We get rid of parentheses

X-(-(+7/2)(X-7))-3=0

We multiply parentheses ..

-(-(+7X^2+7/2*-7))+X-3=0

We multiply all the terms by the denominator


-(-(+7X^2+7+X*2*-7))-3*2*-7))=0


We calculate terms in parentheses: -(-(+7X^2+7+X*2*-7)), so:

-(+7X^2+7+X*2*-7)

We get rid of parentheses

-7X^2-X*2*-7+7

We add all the numbers together, and all the variables

-7X^2-X*2*

Wy multiply elements

-7X^2-2X^2

We add all the numbers together, and all the variables

-9X^2

Back to the equation:

-(-9X^2)


We add all the numbers together, and all the variables

-(-9X^2)=0

We get rid of parentheses

9X^2=0

a = 9; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·9·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$X=\frac{-b}{2a}=\frac{0}{18}=0$