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(X-4)(2X+3)=2X^2
We move all terms to the left:
(X-4)(2X+3)-(2X^2)=0
determiningTheFunctionDomain -2X^2+(X-4)(2X+3)=0
We multiply parentheses ..
-2X^2+(+2X^2+3X-8X-12)=0
We get rid of parentheses
-2X^2+2X^2+3X-8X-12=0
We add all the numbers together, and all the variables
-5X-12=0
We move all terms containing X to the left, all other terms to the right
-5X=12
X=12/-5
X=-2+2/5
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