(X-4)(9-x)+(x+6)2=5x2

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Solution for (X-4)(9-x)+(x+6)2=5x2 equation:



(X-4)(9-X)+(X+6)2=5X^2
We move all terms to the left:
(X-4)(9-X)+(X+6)2-(5X^2)=0
determiningTheFunctionDomain -5X^2+(X-4)(9-X)+(X+6)2=0
We add all the numbers together, and all the variables
-5X^2+(X-4)(-1X+9)+(X+6)2=0
We multiply parentheses
-5X^2+(X-4)(-1X+9)+2X+12=0
We multiply parentheses ..
-5X^2+(-1X^2+9X+4X-36)+2X+12=0
We get rid of parentheses
-5X^2-1X^2+9X+4X+2X-36+12=0
We add all the numbers together, and all the variables
-6X^2+15X-24=0
a = -6; b = 15; c = -24;
Δ = b2-4ac
Δ = 152-4·(-6)·(-24)
Δ = -351
Delta is less than zero, so there is no solution for the equation

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