(X-4)(x+4)=54+(x-5)(x-10)

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Solution for (X-4)(x+4)=54+(x-5)(x-10) equation: 



(X-4)(X+4)=54+(X-5)(X-10)

We move all terms to the left:

(X-4)(X+4)-(54+(X-5)(X-10))=0

We use the square of the difference formula

X^2-(54+(X-5)(X-10))-16=0

We multiply parentheses ..

X^2-(54+(+X^2-10X-5X+50))-16=0



We calculate terms in parentheses: -(54+(+X^2-10X-5X+50)), so:

54+(+X^2-10X-5X+50)

determiningTheFunctionDomain
(+X^2-10X-5X+50)+54

We get rid of parentheses

X^2-10X-5X+50+54

We add all the numbers together, and all the variables

X^2-15X+104

Back to the equation:

-(X^2-15X+104)



We get rid of parentheses

X^2-X^2+15X-104-16=0

We add all the numbers together, and all the variables

15X-120=0

We move all terms containing X to the left, all other terms to the right

15X=120

X=120/15

X=8

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