(X-4)+(3x-4)=12

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Solution for (X-4)+(3x-4)=12 equation: 



(X-4)+(3X-4)=12

We move all terms to the left:

(X-4)+(3X-4)-(12)=0

We get rid of parentheses

X+3X-4-4-12=0

We add all the numbers together, and all the variables

4X-20=0

We move all terms containing X to the left, all other terms to the right

4X=20

X=20/4

X=5

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