(X-4)-(2x+3)=(x+5)-(3-5)

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Solution for (X-4)-(2x+3)=(x+5)-(3-5) equation: 



(X-4)-(2X+3)=(X+5)-(3-5)

We move all terms to the left:

(X-4)-(2X+3)-((X+5)-(3-5))=0

We add all the numbers together, and all the variables

(X-4)-(2X+3)-((X+5)-(-2))=0

We get rid of parentheses

X-2X-((X+5)-(-2))-4-3=0



We calculate terms in parentheses: -((X+5)-(-2)), so:

(X+5)-(-2)

We add all the numbers together, and all the variables

(X+5)+2

We get rid of parentheses

X+5+2

We add all the numbers together, and all the variables

X+7

Back to the equation:

-(X+7)



We add all the numbers together, and all the variables

-1X-(X+7)-7=0

We get rid of parentheses

-1X-X-7-7=0

We add all the numbers together, and all the variables

-2X-14=0

We move all terms containing X to the left, all other terms to the right

-2X=14

X=14/-2

X=-7

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