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(X-4)/(2X)+9=(X+6)/X
We move all terms to the left:
(X-4)/(2X)+9-((X+6)/X)=0
Domain of the equation: 2X!=0
X!=0/2
X!=0
X∈R
Domain of the equation: X)!=0We calculate fractions
X!=0/1
X!=0
X∈R
(X-4)*X)/2X^2+(-((X+6)*2X)/2X^2+9=0
We calculate fractions
((X-4)*X)*2X^2)/(2X^2+(*2X^2)+(-((X+6)*2X)*2X^2)/(2X^2+(*2X^2)+9=0
We get rid of parentheses
((X-4)*X)*2X^2)/(2X^2+*2X^2+(-((X+6)*2X)*2X^2)/(2X^2+(*2X^2)+9=0
We calculate fractions
*2X^2+(((X-4)*X)*2X^2)*(2X^2+*2X^2+9)/((2X^2*(2X^2+(*2X^2)+9)+((-((X+6)*2X)*2X^2)*2X^2/((2X^2*(2X^2+(*2X^2)+9)=0
We calculate terms in parentheses: +(((X-4)*X)*2X^2)*(2X^2+*2X^2+9)/((2X^2*(2X^2+(*2X^2)+9)+((-((X+6)*2X)*2X^2)*2X^2/((2X^2*(2X^2+(*2X^2)+9), so:
((X-4)*X)*2X^2)*(2X^2+*2X^2+9)/((2X^2*(2X^2+(*2X^2)+9)+((-((X+6)*2X)*2X^2)*2X^2/((2X^2*(2X^2+(*2X^2)+9
We can not solve this equation
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