(X-4)/5=(2x+3)/2

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Solution for (X-4)/5=(2x+3)/2 equation: 



(X-4)/5=(2X+3)/2

We move all terms to the left:

(X-4)/5-((2X+3)/2)=0

We calculate fractions


X/()+(-((2X+3)*5)/()=0



We calculate terms in parentheses: +(-((2X+3)*5)/(), so:

-((2X+3)*5)/(

We multiply all the terms by the denominator


-((2X+3)*5)



We calculate terms in parentheses: -((2X+3)*5), so:

(2X+3)*5

We multiply parentheses

10X+15

Back to the equation:

-(10X+15)



We get rid of parentheses

-10X-15

Back to the equation:

+(-10X-15)



We get rid of parentheses

X/()-10X-15=0

We multiply all the terms by the denominator


X-10X*()-15*()=0

We add all the numbers together, and all the variables

X-10X*()=0

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