(X-4)x=140

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Solution for (X-4)x=140 equation:



(X-4)X=140
We move all terms to the left:
(X-4)X-(140)=0
We multiply parentheses
X^2-4X-140=0
a = 1; b = -4; c = -140;
Δ = b2-4ac
Δ = -42-4·1·(-140)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-24}{2*1}=\frac{-20}{2} =-10 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+24}{2*1}=\frac{28}{2} =14 $

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