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(X-5)(X+2)=55
We move all terms to the left:
(X-5)(X+2)-(55)=0
We multiply parentheses ..
(+X^2+2X-5X-10)-55=0
We get rid of parentheses
X^2+2X-5X-10-55=0
We add all the numbers together, and all the variables
X^2-3X-65=0
a = 1; b = -3; c = -65;
Δ = b2-4ac
Δ = -32-4·1·(-65)
Δ = 269
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{269}}{2*1}=\frac{3-\sqrt{269}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{269}}{2*1}=\frac{3+\sqrt{269}}{2} $
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