(X-5)(x-3)=(x+10)(x-4)

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Solution for (X-5)(x-3)=(x+10)(x-4) equation: 



(X-5)(X-3)=(X+10)(X-4)

We move all terms to the left:

(X-5)(X-3)-((X+10)(X-4))=0

We multiply parentheses ..

(+X^2-3X-5X+15)-((X+10)(X-4))=0



We calculate terms in parentheses: -((X+10)(X-4)), so:

(X+10)(X-4)

We multiply parentheses ..

(+X^2-4X+10X-40)

We get rid of parentheses

X^2-4X+10X-40

We add all the numbers together, and all the variables

X^2+6X-40

Back to the equation:

-(X^2+6X-40)



We get rid of parentheses

X^2-X^2-3X-5X-6X+15+40=0

We add all the numbers together, and all the variables

-14X+55=0

We move all terms containing X to the left, all other terms to the right

-14X=-55

X=-55/-14

X=3+13/14

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