(X-5)*(x+4)-(x-8)*(x+8)=7x

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Solution for (X-5)*(x+4)-(x-8)*(x+8)=7x equation: 



(X-5)(X+4)-(X-8)(X+8)=7X

We move all terms to the left:

(X-5)(X+4)-(X-8)(X+8)-(7X)=0

We add all the numbers together, and all the variables

-7X+(X-5)(X+4)-(X-8)(X+8)=0

We use the square of the difference formula

X^2-7X+(X-5)(X+4)+64=0

We multiply parentheses ..

X^2+(+X^2+4X-5X-20)-7X+64=0

We get rid of parentheses

X^2+X^2+4X-5X-7X-20+64=0

We add all the numbers together, and all the variables

2X^2-8X+44=0

a = 2; b = -8; c = +44;
Δ = b2-4ac
Δ = -82-4·2·44
Δ = -288
Delta is less than zero, so there is no solution for the equation

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