(X-5)+(x+5)+(2x-10)+(2x-10)=12

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Solution for (X-5)+(x+5)+(2x-10)+(2x-10)=12 equation: 



(X-5)+(X+5)+(2X-10)+(2X-10)=12

We move all terms to the left:

(X-5)+(X+5)+(2X-10)+(2X-10)-(12)=0

We get rid of parentheses

X+X+2X+2X-5+5-10-10-12=0

We add all the numbers together, and all the variables

6X-32=0

We move all terms containing X to the left, all other terms to the right

6X=32

X=32/6

X=5+1/3

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