(X-5)+(x-4)+5=26+(x-10)

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Solution for (X-5)+(x-4)+5=26+(x-10) equation: 



(X-5)+(X-4)+5=26+(X-10)

We move all terms to the left:

(X-5)+(X-4)+5-(26+(X-10))=0

We get rid of parentheses

X+X-(26+(X-10))-5-4+5=0



We calculate terms in parentheses: -(26+(X-10)), so:

26+(X-10)

determiningTheFunctionDomain
(X-10)+26

We get rid of parentheses

X-10+26

We add all the numbers together, and all the variables

X+16

Back to the equation:

-(X+16)



We add all the numbers together, and all the variables

2X-(X+16)-4=0

We get rid of parentheses

2X-X-16-4=0

We add all the numbers together, and all the variables

X-20=0

We move all terms containing X to the left, all other terms to the right

X=20

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