(X-5)/3=(x+2)/10

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Solution for (X-5)/3=(x+2)/10 equation: 



(X-5)/3=(X+2)/10

We move all terms to the left:

(X-5)/3-((X+2)/10)=0

We calculate fractions


X/()+(-((X+2)*3)/()=0



We calculate terms in parentheses: +(-((X+2)*3)/(), so:

-((X+2)*3)/(

We multiply all the terms by the denominator


-((X+2)*3)



We calculate terms in parentheses: -((X+2)*3), so:

(X+2)*3

We multiply parentheses

3X+6

Back to the equation:

-(3X+6)



We get rid of parentheses

-3X-6

Back to the equation:

+(-3X-6)



We get rid of parentheses

X/()-3X-6=0

We multiply all the terms by the denominator


X-3X*()-6*()=0

We add all the numbers together, and all the variables

X-3X*()=0

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